Under what circumstances would a quadratic inequality have a solution set that is a closed interval? - under
Can anyone help me with this? The teacher was not in the class, and we want to do homework, and I'm lost. Everything would be great ... Thank you very much
Under what circumstances, a second degree inequality, a number of solutions have is a closed interval? Under what circumstances, a second degree inequality have a number of vacuum solutions? Give an example for each situation.
Monday, December 7, 2009
Under Under What Circumstances Would A Quadratic Inequality Have A Solution Set That Is A Closed Interval?
1 comment:
Inequality as a quadratic
-AX ^ 2 + bx + c => 0,
where b ^ 2 - 4ac => 0, the conditions.
I have b ^ 2 - 4ac => 0, because it ensures that the function
f (x) =- x ^ 2 + BX + C
has real roots.
the graph of f (x) =- x ^ 2 + BX + C is set to fall. So (x) => 0, f only for x values from their roots. thus, solutions
-AX ^ 2 + bx + c => 0, belong to the roots, so that a closed interval.
other forms of inequality quadratic
* Ax 2 + bx + c \\ \\ \\ \\ \\ \\ \\ \\ u0026lt j = 0, where b ^ 2 - 4ac => 0 has a closed interval solution.
2) The inequality of the second degree,
* Ax 2 + bx + c \\ \\ \\ \\ \\ \\ \\ \\ u0026lt j = 0, where b ^ 2 - 4ac \\ \\ \\ \\ \\ \\ \\ \\ u0026lt; 0 has a solution to empty set.
under the same conditions,-ax ^ 2 + bx + c => 0 also has a number of vacuum solutions.
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